Hofmann Elimination, Amine to Alkene (aka Exhaustive Methylation)

Описание к видео Hofmann Elimination, Amine to Alkene (aka Exhaustive Methylation)

1. Add excess CH3I (methyl iodide) to make -NH2 into -N(CH3)3+
2. Addition of Ag2O will precipitate AgI and leave OH- leftover
3. OH- will help perform E2 elimination with N(CH3)3 as leaving group.

Check me out: http://www.chemistnate.com

Комментарии

Информация по комментариям в разработке