Скачать или смотреть A particle travels along a straight-line path suchthat in 4 s it moves from an initial position

A particle travels along a straight-line path such
that in 4 s it moves from an initial position sA = -8 m to a
position sB = +3 m. Then in another 5 s it moves from sB to
sC = -6 m. Determine the particle’s average velocity and
average speed during the 9-s time interval.













Answer













*Given Data:*
Initial position: *sA = -8 m*
Intermediate position: *sB = +3 m*
Final position: *sC = -6 m*
Time from A to B: *tAB = 4 s*
Time from B to C: *tBC = 5 s*
Total time: *tTotal = 4 s + 5 s = 9 s*

*Step 1: Compute Average Velocity*
*Formula:* *v_avg = (Total Displacement) / (Total Time)*
*Displacement:* *sC - sA = -6 m - (-8 m) = 2 m*
*v_avg = (2 m) / (9 s) = 0.222 m/s*

*Step 2: Compute Average Speed*
*Formula:* *Speed_avg = (Total Distance) / (Total Time)*
*Distance Traveled:*
*|sB - sA| = |3 - (-8)| = 11 m*
*|sC - sB| = |-6 - 3| = 9 m*
*Total Distance = 11 m + 9 m = 20 m*
*Speed_avg = (20 m) / (9 s) = 2.22 m/s*

*Final Answers:*
*Average Velocity = 0.222 m/s*
*Average Speed = 2.22 m/s*