Force required to LIFT an object against Gravity || Work and Energy || in Hindi for Class 9

In this Science (Physics) video in Hindi for Class 9 we explained how force required to lift an object against gravity is equal to mg. This is a topic from Chapter 11 - 'Work and Energy' for class 9th from NCERT.

As we know, if applied force is equal to the force due gravity, the object will be at rest. But for a brief period of time we incease the applied force a little bit which creates a non zero nt force. It produces an acceleration and hence, a velocity is created. Then, we continue the force which is equal to the force due to gravity. This produces a zero acceleration but the body continues its velocity (Newton's first law of motion). After sometimes, for a brief period of time we decease the applied force a little bit which produces a deceleration and hence, the body stops. In this period the body is being lifted to the required height.

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🔴 Click here to watch the whole playlist on Chapter 11 : 'Work and Energy' for Class 9 :

   • Work and Energy (Introduction) || in ...  

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Previous videos :-

🔴 Work and Energy (Introduction)
   • Work and Energy (Introduction) || in ...  

🔴 What is Work
   • What is Work ?? (Work and Energy - 2)...  

🔴 Sine, Cosine and Tangent (Trigonometry)
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🔴 Advanced concept on Work (Dot Product)
   • Advanced concept on Work (Dot Product...  

🔴 Kinetic Energy
   • Kinetic Energy || Work and Energy || ...  

🔴 Kinetic Energy - Part 2 (Numericals)
   • Kinetic Energy - Part 2 (Numericals) ...  

🔴 Kinetic Energy is Relative to the Observer
   • Kinetic Energy is Relative to the Obs...  

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