Скачать или смотреть Day 12: Linked List – Part 2 | 50 Days DSA Practice in C++ by LogicNLearn

Welcome to Day 12 of our "50 Days DSA Practice in C++" series by LogicNLearn!
Today, we continue exploring the world of **Linked Lists**, diving into more **intermediate-level problems**. You'll master reversing a linked list, finding the middle node, removing the Nth node from the end, and more!

📌 *Problems Covered Today:*

1️⃣ Reverse a Linked List – GFG
👉 [https://www.geeksforgeeks.org/problem...](https://www.geeksforgeeks.org/problem...)

2️⃣ Middle of the Linked List – LeetCode
👉 [https://leetcode.com/problems/middle-...](https://leetcode.com/problems/middle-...)

3️⃣ Remove Nth Node From End of List – LeetCode
👉 [https://leetcode.com/problems/remove-...](https://leetcode.com/problems/remove-...)

4️⃣ Remove Duplicates from Sorted Linked List – GFG
👉 [https://www.geeksforgeeks.org/problem...](https://www.geeksforgeeks.org/problem...)

5️⃣ Move Last Element to Front – GFG
👉 [https://www.geeksforgeeks.org/problem...](https://www.geeksforgeeks.org/problem...)

📝 *Notes:*
📎 [Day 12 Linked List Notes – Excalidraw](https://excalidraw.com/#json=y6JghIKJ...)


🔗 GitHub Repo:
https://github.com/yash88990/50-DAYS-...



📺 Watch the Full Series Playlists:

📌 50 Days DSA Practice in C++ by LogicNLearn
[https://youtube.com/playlist?list=PLV...\_9eLFP](   • Плейлист  )

📌 50 Days DSA in C++ by LogicNLearn
[   • 50 Days DSA in CPP by LogicNLearn  ](   • 50 Days DSA in CPP by LogicNLearn  )

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📚 *What You'll Learn Today:*

How to reverse a singly linked list (iterative + recursive)
Efficiently finding the middle node in one pass (Tortoise-Hare method)
Removing the Nth node from the end in a single traversal
Handling sorted lists by removing duplicates
Linked list manipulation tricks like moving the last node to the front

🎯 Whether you're a beginner or brushing up for interviews, these linked list problems are **must-practice**!

📢 Subscribe for more daily DSA & C++ explanations!
💬 Drop your questions in the comments — I personally reply to everyone!

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