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Let, Generated Hamming code 1010010
In the receiver end data is changed, after changing data become 1011010
Step 1: For checking parity bit P1, use check one and skip one method, which means, starting from P1 and then skip P2, take D3 then skip P4 then take D5, and then skip D6 and take D7, this way we will have the following bits.
As we can observe that the number of 1's are even, then we will write the value of P1=1 ⊕1 ⊕0 ⊕0 = 0. This means there is no error.
#ErrorDetection&Correction

Step 2: Check for P2 but while checking for P2, we will use check two and skip two method, which will give us the following data bits. But remember since we are checking for P2, so we have to start our count from P2 (P1 should not be considered).
As we can observe that the number of 1's are even, then we will write the value of P2=1 ⊕0 ⊕0 ⊕1 = 0. This means there is no error.
Step 3: Check for P4 but while checking for P4, we will use check four and skip four method, which will give us the following data bits. But remember since we are checking for P4, so we have started our count from P4(P1 & P2 should not be considered).
As we can observe that the number of 1's are even, then we will write the value of P4=1 ⊕0 ⊕0=1 ⊕1 = 1. This means there is error.
so we can clearly say that the received hamming code has errors.
Hamming Code: Error Correction
Since we found that received code has an error, so now we must correct them. To correct the errors, use the following steps:
Now the error word E will be:
Now we have to determine the decimal value of this error word 100 which is 4
We get E = 4, which states that the error is in the Fourth data bit. To correct it, just invert the Fourth data bit.