Скачать или смотреть Cylinder, Cone and Sphere | ICSE Class 10 | Maths Online Class | Session 2 - Swiflearn

In this Session of Cylinder, Cone and Sphere, Shashank Sir will take you through the following important topics from the chapter Session of Cylinder, Cone and Sphere from ICSE Class 10 Math,

Learning Objectives

🔯Define cone or right circular cone.

🔯Latent height of a cone.

🔯Formulas to find the volume, curved surface area and total surface area of a cone.

🔯Solve the questions based on cone.

-----------------------------------------------------------------------------

🔸Now you can visit Swiflearn YouTube Channel to attend the LIVE classes that will cover your entire syllabus

@SwifLearn is India's best platform for LIVE face-to-face online tuitions. Access to India's best teachers from the comfort of your homes

#heatandenergy #icse #class9 #swiflearn #onlineclasses

🔸SwifLearn provides LIVE ONLINE Face-to-Face Tuitions for Classes 1 to 10.

🔸Book a Free Trial Class; Visit our website: https://www.swiflearn.com?

🔸Stay in touch:
Visit our Facebook page:   / swiflearn  
Visit our Instagram page:   / swiflearn  
Visit our LinkedIn page:   / swif.  .
Download our App : https://play.google.com/store/apps/de...
-------------------------------------------------------------------------

To download FREE revision notes of this chapter visit this link:
https://swiflearn.com/revision-notes/...
-------------------------------------------------------------------------

Cylinder, Cone and Sphere

Cylinder
The lateral (or curved) surface area of a cylinder is2πrh.
The total surface of a cylinder =2πr(r + h)
Volume of the cylinder =𝜋𝑟2ℎ
Area of the cross section =𝜋𝑟2
Perimeter of the cross section = 2d + 2h where d is the diameter of the cylinder Hollow cylinder
Thickness of the wall = R − r
Area of cross section =𝜋(𝑅2−𝑟2)
External curved surface area =2πRh
Internal curved surface area =2πrh
Volume of the material =𝜋(𝑅2−𝑟2)ℎ
Total surface area =2𝜋𝑅ℎ+2𝜋𝑟ℎ+2𝜋(𝑅2−𝑟2)

Sphere
A sphere is a solid obtained by revolving a circle about any of its diameter
Total surface area =4𝜋𝑟2
Volume =43𝜋𝑟3Spherical shell
It is a solid enclosed between two concentric spheres
Volume =43𝜋(𝑅3−𝑟3)Conversion of solid from one shape to another
When a solid is converted from one shape to other, the volume of the solid remains the same.
When a liquid is poured from one container of particular shape and size into another container of a different shape and size, the volume of the liquid remains the same. Points to remember for cross-sectional problems
Volume = area of the cross section × length
Surface area (excluding cross section) = perimeter of the cross section × length

Frustum of a cone
Surface area and volume of the frustum of a cone whereR2 is greater than R1.
Volume =13𝜋ℎ(𝑟12+𝑟1𝑟2+𝑟22)
Curved surface area =𝜋(𝑟1+𝑟2)𝑙; Where l=√ℎ2+(𝑟2−𝑟1)2
Total surface area =𝜋(𝑟1+𝑟2)𝑙+𝜋𝑟12+𝜋𝑟22Surface area of combination of solids
The total surface area of a combination of solids is equal to the total curved surface area visible to our eyes.
We shouldn’t add the surface areas of the two constituent shapes because some part of the surface area gets merged when the two shapes are combined. Example: Surface area of a combination of hemispheres and cylinder
The total surface area of the new solid is equal to the sum of the curved surface areas of each of the individual parts.
TSA of the new solid = CSA of one hemisphere + CSA of cylinder + CSA of the other hemisphere.

Volume of combination of solids
The volume of a solid formed by combining two basic solids is equal to the sum of volumes of the individual solids.