x,y,z sides of right triangle, z= hypotenuse. Prove that radius of the in-circle, r=(x+y-z)/2

Описание к видео x,y,z sides of right triangle, z= hypotenuse. Prove that radius of the in-circle, r=(x+y-z)/2

In the given figure x,y,z are the sides of a right angled triangle where z is the hypotenuse. Prove that the radius of the circle which touches the sides of the triangle is given by r=(x+y-z)/2

radius of in circle of a right angled triangle in terms of sides of the triangle

cbse class 10 mathematics old board exam question paper supplementary exam June 2023 2024 question in circles based on tangents drawn to a circle from an external point are equal

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