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Скачать или смотреть 🚀 Particular Integral Type 1 e^ax Higher Order Differential Equations | VTU Engineering Mathematics

  • MUDASSIR ACADEMY
  • 2025-10-14
  • 802
🚀 Particular Integral Type 1 e^ax Higher Order Differential Equations | VTU Engineering Mathematics
engineering mathematicsHigher Order Differential Equationshigher order linear differential equationsdifferential equations higher orderlinear differential equation with constant coefficienthigher order differential equations engineering mathematicsperticular integralbmatec301bmatec301 module 421mat21
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Описание к видео 🚀 Particular Integral Type 1 e^ax Higher Order Differential Equations | VTU Engineering Mathematics

Let's start finding the 📌Particular Integral for Higher Order Differential Equations. Today, we will solve Particular Integral Type 1, where the right-hand side is of the form e^Ax

In differential equations of higher order, the general solution is:
✨y = Complementary Function (C.F.) + Particular Integral (P.I.)
Particular Integral – Type 1 e^ax/f(D)

If you haven't watched the previous video on linear higher order differential equations with constant coefficients , please check it first — it is very important for understanding Complementary Functions. ▶️
Watch here:    • ⭐Solve (4d⁴ - 8d³ - 7d² + 11d + 6)y=0 &(4d...  

✅ VTU Syllabus Codes Covered
18MAT21, 21MAT21, BMATC101, BMATE101, BMATM101, 1BMATC101, 1BMATM101, 1BMATE101, BMATEC301

📝 Problems Solved in This Video (Particular Integral Type 1 or case 1)

(6D² + 17D + 12) y = e^(-x) + 4

(D² - 4D + 4) y = sinh(2x) + 2^x

(D⁴ - 18D² + 81) y = 36 e^x

Follow along step-by-step to learn how to solve these exam-important problems 📝

📚 Playlists for Chapter-wise Engineering Mathematics & Polytechnic Subjects

Engineering Mathematics 1 Playlist:    • 21MAT21 VTU ADVANCED CALCULUS AND NUMERICA...  

Engineering Mathematics 2 Playlist:    • 21MAT11 | CALCULUS AND DIFFERENTIAL EQUATI...  

These playlists cover all universities across India and help you prepare for exams efficiently 🎯

01:30 Introduction to particular integral type 1 where RHS is e^ax
10:40 (6D² + 17D + 12) y = e^(-x) + 4
17:52 (D² - 4D + 4) y = sinh(2x) + 2^x
28:00 (D⁴ - 18D² + 81) y = 36 e^x

Correction:
25:22 really sorry i went with flow and forgot the basics actually (log3)^2 keep it as it is in solution
25:30 (log3)^2 not equal to 2log3 bcoz the formula is log(a)^k=klog a .
25:36 Sorry for mistake So (log3)^2 keep it as it is in solution till end
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#EngineeringMathematics #VTU #DifferentialEquations #ParticularIntegral #HigherOrderDE
#EngineeringMathematics #HigherOrderDifferentialEquations #LinearDifferentialEquations #ConstantCoefficientODE #ParticularIntegral #BMATEC301 #21MAT21 #ComplementaryFunction #DifferentialEquations #ODE#HigherOrderODE #EngineeringMath

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