Скачать или смотреть 28 Conditional Trigonometric Identities | Full Explanation & Proofs | SEE/NEB Maths

28 Conditional Trigonometric Identities | Full Explanation & Proofs | SEE/NEB Maths

In this video, we solve and prove some important trigonometric identities step by step.
These problems are taken from Class 10 Mathematics (Chapter: Conditional Trigonometric Identities) and are very useful for board exams and entrance preparation.

📚 Topics Explained:
Master Conditional Trigonometric Identities with this complete step-by-step explanation video!
In this session, we cover all key questions based on A + B + C = π, including:
✅ Definition of Conditional Trigonometric Identities with Example
✅ True Condition for the Identity tanA = cotB
✅ Relations Derived from A + B + C = π
✅ Detailed Proofs of Trigonometric Identities like:
 • tanA + tanB + tanC = tanA·tanB·tanC
 • tan(A/2)tan(B/2) + tan(B/2)tan(C/2) + tan(C/2)tan(A/2) = 1
 • cotA·cotB + cotB·cotC + cotC·cotA - 1 = 0
 • and more!

Questions Covered in This Video:

1. a. Define conditional trigonometric identities with example.
b. What is the true condition for the identity tanA = cotB?
c. Write any three relations which can be formed from A + B + C = π.

2. If A + B + C = π, prove that:
a. tanA + tanB + tanC = tanA * tanB * tanC
b. tan(A/2) * tan(B/2) + tan(B/2) * tan(C/2) + tan(C/2) * tan(A/2) = 1
c. tan2A + tan2B + tan2C = tan2A * tan2B * tan2C
d. cotA * cotB + cotB * cotC + cotC * cotA - 1 = 0
e. cot2A * cot2B + cot2B * cot2C + cot2C * cot2A = 1


💡 Watch till the end to understand each proof clearly!
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