Скачать или смотреть How to Prepare 500 PPM of Lead Nitrate | Pb(No3)2 | in 25 ml.

This video provides a comprehensive guide on how to prepare a 500 PPM (Parts Per Million) solution, specifically focusing on a lead nitrate solution in a 25 mL volume.
The video starts by explaining the concept of PPM as "one part of solute in one million 10^6 parts of solution" and presents the formula:
PPM = Mass of Solute (g)\Mass of Solution (g) * 10^6
It clarifies that 1 PPM is approximately equal to 1 milligram of solute per 1 liter of water, explaining the conversion between units.
The example then demonstrates the calculation for preparing the 500 PPM lead nitrate solution. It highlights that in such solutions, the primary concern is usually the metal component (lead in this case) as metals are often present in salt form. The video shows the step-by-step process of converting 500 mg/L to grams and applying a unitary method involving the molar masses of lead and lead nitrate to determine the required mass of lead nitrate for 1000 mL. Finally, it calculates the exact amount needed for a 25 mL solution.
This video is perfect for students, researchers, or anyone needing to understand and practically apply solution concentration calculations, particularly for PPM solutions.
You can also try to find out different concentration like 10 ppm or dilution ..
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