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Скачать или смотреть How to Fetch Records with Different Column Values by Date in PostgreSQL

  • vlogize
  • 2025-09-15
  • 0
How to Fetch Records with Different Column Values by Date in PostgreSQL
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Описание к видео How to Fetch Records with Different Column Values by Date in PostgreSQL

Learn how to efficiently retrieve records in PostgreSQL where specific vehicle types follow certain criteria based on dates.
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This video is based on the question https://stackoverflow.com/q/62522503/ asked by the user 'dreambigcoder' ( https://stackoverflow.com/u/2205016/ ) and on the answer https://stackoverflow.com/a/62522616/ provided by the user 'GMB' ( https://stackoverflow.com/u/10676716/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: postgresql to fetch records with different column values by date

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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How to Fetch Records with Different Column Values by Date in PostgreSQL

When working with databases, it's not uncommon to encounter scenarios where you need to filter data based on specific conditions. One such task is fetching records from a PostgreSQL database where certain column values occur in a particular order by date. In this guide, we will explore a specific use case involving vehicle types and user IDs in a PostgreSQL table, and we will provide a detailed solution for this problem.

The Problem

Imagine you have a table named user with the following structure:

user_idvehicle_typecreated_date1102020-06-012112019-09-09192020-06-02122020-02-012102019-09-06292019-09-11You want to fetch records for a particular user (let's say user_id 1) with vehicle types of 10 and 9, but only if the vehicle type of 10 is followed by the vehicle type of 2 on a later date. Your requirement excludes any records of user_id 2 if their 10 is followed by a 11 vehicle type before a 9 shows up.

The Solution

To achieve this, we can utilize the lead() window function in PostgreSQL. The lead() function allows us to access data from subsequent rows without the need for complex self-joins, making it a powerful tool for analyzing ordered datasets.

Step-by-Step Breakdown

Here is the SQL query that you can use:

[[See Video to Reveal this Text or Code Snippet]]

Query Explanation

Select Data:

The inner query selects all columns from the users' table, along with the next vehicle type for each user based on the order of the created date.

Using lead():

lead(vehicle_type) OVER (PARTITION BY user_id ORDER BY created_date) retrieves the vehicle type of the next row for the same user, ordered by the created date.

Filtering Results:

The outer query then filters for rows where the vehicle_type is either 9 or 10, and checks that the following vehicle_type (obtained from the lead() function) equals 2.

Result Interpretation

The final result will include only those records for user_id 1:

user_idvehicle_typecreated_date1102020-06-01192020-06-02As shown in the results, there's no entry for user_id 2 since 11 exists between the vehicle types, thereby satisfying our filtering condition.

Conclusion

In conclusion, using the lead() function in PostgreSQL allows you to efficiently retrieve records based on the conditions specified in your queries. This approach simplifies the data retrieval process and enhances performance, especially with larger datasets. The method we discussed can be adapted to various scenarios where you need to analyze sequential data chapters, making it a valuable asset in your SQL toolbox.

Feel free to try this approach and modify it to suit your specific use cases! If you have any questions or need further assistance, don't hesitate to reach out.

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