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Скачать или смотреть How to Deserialize JSON Objects into a Flatten Format in Java

  • vlogize
  • 2025-09-08
  • 0
How to Deserialize JSON Objects into a Flatten Format in Java
How to deserialize json object into flatten format direct field?javajsonspring bootjackson
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Описание к видео How to Deserialize JSON Objects into a Flatten Format in Java

Learn how to flatten your JSON objects in Java using Jackson's JSON serialization features effectively.
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This video is based on the question https://stackoverflow.com/q/63373979/ asked by the user 'badCoder' ( https://stackoverflow.com/u/3452571/ ) and on the answer https://stackoverflow.com/a/63407016/ provided by the user 'badCoder' ( https://stackoverflow.com/u/3452571/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to deserialize json object into flatten format direct field?

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Deserializing JSON Objects into Flatten Format in Java

When developing applications in Java, especially with frameworks like Spring Boot, you may find yourself needing to manipulate and format JSON data in specific ways. One common challenge is flattening out nested objects to make APIs simpler and easier to consume. In this guide, we will address the specific problem of deserializing a JSON object into a flattened format for a user-defined class structure.

The Problem

Let's consider a scenario where you have two classes, User and Account, as shown below:

[[See Video to Reveal this Text or Code Snippet]]

You might request data that appears as follows:

[[See Video to Reveal this Text or Code Snippet]]

However, you might prefer to simplify this response, flattening the structure to ignore the description entirely and directly represent the account ID, like so:

[[See Video to Reveal this Text or Code Snippet]]

The challenge lies in achieving this format using Jackson's serialization/deserialization capabilities without creating unnecessary fields or structures in your code.

The Solution

To accomplish this, you can leverage the @ JsonCreator and @ JsonProperty annotations provided by Jackson. Here's how to set it up step-by-step:

Step 1: Modify the Account Class

You will need to create two constructors in your Account class: one for regular use and another specifically tailored for the ID only. This allows Jackson to choose the appropriate constructor when deserializing the JSON. Here’s the modified Account class code:

[[See Video to Reveal this Text or Code Snippet]]

Step 2: Deserialize Using the User Class

When you create a User object, Jackson will now be able to interpret the incoming JSON structure properly. Even if the request only includes the id, if it's in the correct format, Jackson will understand how to populate your Account class accordingly.

How It Works

By introducing multiple constructors marked with @ JsonCreator, you enable Jackson to recognize and use the constructor that best matches the provided JSON keys. If the JSON input includes both the id and description fields, Jackson will use the first constructor. If it only includes the id, the second constructor kicks in, allowing for a seamless conversion to the desired flattened format.

Conclusion

Flattening JSON objects in Java using Jackson can be handled elegantly by customizing constructors in your model classes with annotations. This method not only preserves the original structure when necessary but also provides the flexibility needed when you want to simplify your API responses.

By leveraging @ JsonCreator and @ JsonProperty, you can smoothly adapt to various data formats expected in your applications, helping maintain clarity and efficiency in your code!

Now you're equipped to handle JSON deserialization effectively and create cleaner API outputs that meet your specific needs. Happy coding!

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