Solutions Chemistry Class 12 | Chapter 2 | CBSE NEET JEE

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Timestamps:
0:00 Introduction
0:45 Solutions
5:53 Solutions:Solvent&Solute
8:55 Solutions:BinarySolutions
9:29 Solutions:Types
9:53 Solutions:GaseousSolution
11:25 Solutions:Liquid Solution
12:37 Solutions:Solid Solution
14:45 Solutions:Concentration
17:15 Solutions:Quantitative concentration
17:52 Mass Percentage
19:36 Volume Percentage
21:05 Mass by VolumePercentage
22:16 Parts per million
25:30 Mole Fraction
27:17 Mole Fraction:Example
32:57 Molarity
34:58 Molarity:Example
38:07 Molality
40:42 Molality:Example
43:44 Solutions:Quantitative Concentration
45:50 Problem 1
48:08 Problem 2
56:17 Problem 3

In this video we will cover:
1.NCERT solutions class 12 Chemistry chapter 2 solutions
2.NCERT Class 12 Chemistry chapter 2 Solutions notes
3.What are solutions?
4.Difference between solution and solvent.
5.Explain binary solutions.
6.Different types of solutions.
7.Calculate the mole fraction of ethylene glycol (C2H6O2) in a solution containing 20% of C2H6O2 by mass.
8.Calculate the molarity of a solution containing 5 g of NaOH in 450 mL solution
9.Calculate molality of 2.5 g of ethanoic acid (CH3COOH) in 75 g of benzene
10.Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride
11.Solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL–1, then what shall be the molarity of the solution?
13.A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

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