Proof Binomial to Poisson Distribution || Lesson 56 || Probability & Statistics || Learning Monkey

Proof Binomial to Poisson Distribution
In this class, We discuss Proof Binomial to Poisson Distribution.
The reader should have prior knowledge of Poisson distribution. Click Here.
We understand how we got the probability mass function of the Poisson distribution.
In poisson we have λ value.
λ = np
p = λ/n
Assumption: n - ∞ and p - 0
In the coming classes, we discuss why we assume n - ∞ and p - 0.
The below diagram shows the proof of Binomial to Poisson distribution.
We take the binomial distribution equation.
We derive the probability mass function of Poisson distribution with the assumptions n - ∞ and p - 0.
Proof: Poisson probability mass function is a discrete probability function
In binomial distribution as n = 10
The random variable X is having values 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
In poisson n - ∞
The random variable X = 0, 1, 2, . . , ∞
The below diagram shows the proof sum of all probabilities in Poisson = 1.

Link for playlists:
   / @learningmonkey  


Link for our website: https://learningmonkey.in

Follow us on Facebook @   / learningmonkey  

Follow us on Instagram @   / learningmonkey1  

Follow us on Twitter @   / _learningmonkey  

Mail us @ [email protected]