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Скачать или смотреть Understanding lastIndexOf() in JavaScript: Why It Returns -1

  • vlogize
  • 2025-05-25
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Understanding lastIndexOf() in JavaScript: Why It Returns -1
really simple question about why lastIndexOf() returns -1 in this casejavascriptlastindexof
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Описание к видео Understanding lastIndexOf() in JavaScript: Why It Returns -1

Discover why `lastIndexOf()` might return -1 when searching for a character in a string, and how to correctly use this function with escape sequences in JavaScript.
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This video is based on the question https://stackoverflow.com/q/68144796/ asked by the user 'hamdi salim' ( https://stackoverflow.com/u/16322205/ ) and on the answer https://stackoverflow.com/a/68144818/ provided by the user 'CertainPerformance' ( https://stackoverflow.com/u/9515207/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: really simple question about why lastIndexOf() returns -1 in this case

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Understanding lastIndexOf() in JavaScript: Why It Returns -1

JavaScript's lastIndexOf() method is a powerful tool when you want to find the last occurrence of a specified character or substring within a string. However, there are times when the method returns -1, indicating that the character or substring was not found. In this post, we’ll explore a common scenario in which lastIndexOf() might return -1, helping you understand this behavior for better coding practices.

The Problem Explained

Suppose you have a string that includes newline characters represented by the escape sequence \n, and you want to find the last index of the letter n. You might expect the method to return the last occurrence's index, possibly something above 200. Instead, it returns -1. You may wonder: Why does this happen?

Here’s a snippet of code that illustrates this issue:

[[See Video to Reveal this Text or Code Snippet]]

The Explanation

The key reason behind the return value of -1 is that the string s does not contain any literal n characters. Instead, it includes sequences of characters like \n which represent newline characters.

Understanding Escape Sequences

When you write:

[[See Video to Reveal this Text or Code Snippet]]

It is equivalent to a string that has a newline character:

[[See Video to Reveal this Text or Code Snippet]]

In this example, there is no individual character n present. What you see is simply a representation of the string with escape sequences.

Finding n in Literal Strings

If you want to include literal \n characters (the characters themselves, rather than the newline), you can use String.raw. This method treats backslashes as literal characters, preventing JavaScript from interpreting them as escape characters:

[[See Video to Reveal this Text or Code Snippet]]

Finding Newline Characters

If you need to find where the newline characters themselves (not the character ‘n’) are located within the string, you should use the newline character in your lastIndexOf() function:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

In summary, the lastIndexOf() method returns -1 when searching for a character that does not exist in the string, which is often due to confusion around escape sequences like \n. By understanding how escape sequences work and utilizing String.raw when necessary, you can accurately find indices within string data in JavaScript.

Stay mindful of the characters you are searching for, and ensure they match the expected format in your strings to avoid unexpected results. Happy coding!

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