Скачать или смотреть In an n-p-n transistor, 200 electrons enter the emitter in 10–8 s. If 1% electrons | PGMN Solutions

In an n-p-n transistor, 200 electrons enter the
emitter in 10–8 s. If 1% electrons are lost in the
base, then the current that enters the emitter and
the current amplification factor are respectively
(A) 3.2 × 10–9 A and 99
(B) 2 × 10–10 A and 49
(C) 1.7 × 10–11 A and 70
(D) 1.6 × 10–19 A and 90



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🚀 Step-by-Step Solution to Solve This Question 🚀
📌 Chapter: Semiconductor Device
📌 Topic: Current Amplification in n-p-n Transistor

🔹 Step 1: Introduce the core concept related to the question
In an n-p-n transistor, the emitter injects electrons into the base region. Most of these electrons pass through the base and reach the collector, contributing to the collector current. Only a small fraction of electrons combine in the base, forming the base current.

🔹 Step 2: Explain how the concept applies to the given situation
Here, electrons are entering the emitter over a short time interval. Since only a small percentage of these electrons are lost in the base, most of them contribute to the output current at the collector.

🔹 Step 3: Break down the logical steps required to solve the problem

The total number of electrons entering the emitter indicates the total current supplied by the emitter.

If only 1% of electrons are lost in the base, it means 99% successfully reach the collector.

The base current is small, and the collector current is almost equal to the emitter current.

The current amplification factor is the ratio of the collector current to the base current, and since the base current is very small, the ratio becomes large.

🔹 Step 4: Explain the final theoretical conclusion
Since only 1% of the electrons are lost in the base, the amplification factor is high—almost 99. And based on the number of electrons and the time interval, the current entering the emitter is in the nanoampere range.

✅ Final Answer: (A) 3.2 × 10⁻⁹ A and 99 🚀

🔥 Pro Tip: In transistor questions, when the loss in the base is very small, the amplification factor becomes very high. Always focus on how efficiently the emitter-to-collector transfer happens to judge the amplification.


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