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Скачать или смотреть Replacing Values in PHP Arrays

  • vlogize
  • 2025-09-21
  • 0
Replacing Values in PHP Arrays
Replace the values ​of one array based on the values in another arrayphparraysmultidimensional array
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Описание к видео Replacing Values in PHP Arrays

Learn how to efficiently replace the values of one PHP array based on another, using simple nested loops.
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This video is based on the question https://stackoverflow.com/q/62765086/ asked by the user 'Legion' ( https://stackoverflow.com/u/13151449/ ) and on the answer https://stackoverflow.com/a/62765375/ provided by the user 'FluffyKitten' ( https://stackoverflow.com/u/514878/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Replace the values ​of one array based on the values in another array

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Replacing Values in PHP Arrays: A How-To Guide

Managing data in PHP can sometimes become complicated, especially when dealing with arrays containing nested structures. One common problem developers encounter is the need to replace the values of one array based on the values in another. In this guide, we’ll break down how to do this effectively with a clear example and solution.

The Problem Statement

Suppose you have two arrays:

Array containing years: $priceYear, which utilizes nested structures.

Replacement array: $array, which contains year-value pairs.

Here’s what the arrays look like:

[[See Video to Reveal this Text or Code Snippet]]

What Do We Want to Achieve?

The goal is to replace the values in $priceYear with the respective VALUE_AMDON from $array, provided the year matches the YEAR field in the replacement array.

For example, all instances of the year 2020 in $priceYear should be replaced by 59, and the year 2019 should become 57.

The Solution: Using Nested Loops

As there is no direct connection between the keys of the arrays, the best and simplest approach is to implement nested loops. Here's a step-by-step breakdown of how to do this.

Step 1: Loop through the $priceYear Array

We'll start iterating over $priceYear. For each entry, we'll check the requirements to modify its values.

Step 2: Check Each "Year" Value

For each "year" within $priceYear, we’ll compare it against the YEAR values in the $array. If there’s a match, we replace the value appropriately.

Step 3: Implement the Code

Here’s the code that accomplishes this task:

[[See Video to Reveal this Text or Code Snippet]]

Sample Data and Outputs

When you run this code with the initial provided arrays, you’ll receive an output like this:

[[See Video to Reveal this Text or Code Snippet]]

Considerations for Non-Existent Years

It’s also essential to handle cases where the years do not exist in $array. For example, a year 2021 will default to 0 since it doesn't have a corresponding value in the $array.

Conclusion

Replacing values in associative arrays based on conditions can be accomplished effectively with nested loops in PHP. The above approach not only solves the problem but does so in a clear and maintainable way.

Armed with this knowledge, you should be well on your way to manipulating arrays in PHP like a pro!

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