Learn how to efficiently compare two lists of objects in Python, focusing on both their contents and identities while ignoring order.
---
This video is based on the question https://stackoverflow.com/q/67987270/ asked by the user 'a276me' ( https://stackoverflow.com/u/14653420/ ) and on the answer https://stackoverflow.com/a/67987436/ provided by the user 'Tom McLean' ( https://stackoverflow.com/u/14720380/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.
Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Comparing contents of lists ignoring order
Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.
If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
Comparing Contents of Lists in Python: Ignoring Order and Object Identity
In the world of Python programming, you may find yourself needing to compare two lists that contain objects. One common situation is wanting to know if the contents of these lists are the same—regardless of their order. This might seem like a straightforward task, but it can get tricky, especially when dealing with custom objects. In this guide, we'll explore how to do this effectively by breaking down the necessary steps and illustrating a solution that accommodates both value equality and identity.
Understanding the Problem
Let's assume you have a custom class OBJ representing an object. You create two lists of instances of this class:
[[See Video to Reveal this Text or Code Snippet]]
Your goal is to determine if the contents of lists a and b are the same, even though they are ordered differently. However, compare methods like sorted() face limitations, particularly when comparing custom objects, as they lack the built-in equality checks necessary for the comparison.
Method 1: Implementing Equality and Less-Than Methods
To effectively compare your objects, you need to override some standard methods in your custom class:
Adding _eq_ and _lt_
__eq__: This method checks if two objects are equal based on their attributes.
__lt__: This method defines how to sort objects, which will help in using the sorted() function.
Here’s how you can implement these methods:
[[See Video to Reveal this Text or Code Snippet]]
Comparing Lists
Now, with these methods in place, you can easily compare your lists:
[[See Video to Reveal this Text or Code Snippet]]
Method 2: Checking Object Identity
If the goal shifts to confirming that two lists not only have the same contents (by value) but also refer to the same object instances, you'll need a different approach. For this, you can use the id() function which returns the identity of an object.
Example Implementation
Let's say you have the following lists:
[[See Video to Reveal this Text or Code Snippet]]
To check if x and y are the same in terms of object identity:
[[See Video to Reveal this Text or Code Snippet]]
Important Note
Consider the following example:
[[See Video to Reveal this Text or Code Snippet]]
In this case, the comparison returns False because even though c and d have the same value, they are distinct objects with different identities.
Conclusion
Comparing lists of objects in Python can either be about their contents or their identities, depending on your needs. By implementing the _eq_ and _lt_ methods, you allow for proper list content comparisons regardless of order. On the other hand, using id() enables checking if the lists refer to the exact same objects. Armed with these techniques, you can tackle most list comparison challenges in Python with confidence.
Now, you are well-equipped to handle object comparisons in Python, no matter how complex the task may seem!
Информация по комментариям в разработке