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*4 to 16 Decoder
In this section, let us implement 4 to 16 decoder using 3 to 8 decoders. We know that 3 to 8 Decoder has three inputs A2, A1 & A0 and eight outputs, Y7 to Y0. Whereas, 4 to 16 Decoder has four inputs A3, A2, A1 & A0 and sixteen outputs, Y15 to Y0

We know the following formula for finding the number of lower order decoders required.
Required number of lower order decoders=m2/m1

Substitute, m1 = 8 and m2 = 16 in the above formula.

Required number of 3 to 8 decoders=16/8=2
Therefore, we require two 3 to 8 decoders for implementing one 4 to 16 decoder.
The parallel inputs A2, A1 & A0 are applied to each 3 to 8 decoder. The complement of input, A3 is connected to Enable, E of lower 3 to 8 decoder in order to get the outputs, Y7 to Y0. These are the lower eight min terms. The input, A3 is directly connected to Enable, E of upper 3 to 8 decoder in order to get the outputs, Y15 to Y8. These are the higher eight min terms.