Скачать или смотреть A steel wire of length 2 m and Young's modulus 2.0 × 10¹¹ Nm⁻² is stretched by a force. If Poisson

A steel wire of length 2 m and Young's modulus 2.0 × 10¹¹ Nm⁻² is stretched by a force. If Poisson ratio and transverse strain for the wire are 0.2 and 10⁻³ respectively, then the elastic potential energy density of the wire is ____ × 10⁵ (in SI units)

📘 JEE Main Physics | Elasticity | Elastic Potential Energy Density ⚙️🧲

This video explains a classic elasticity problem involving a steel wire under tension, a common concept in JEE Main and NEET Physics. Such problems test understanding of stress, strain, and energy stored in materials, rather than just applying formulas.

🧠 Relevant Concepts

1️⃣ Stress and Strain

When a material is stretched or compressed, stress is the force per unit area, and strain is the relative deformation 📐

Longitudinal strain occurs along the direction of applied force, while transverse strain occurs perpendicular to it

2️⃣ Poisson’s Ratio

Ratio of transverse strain to longitudinal strain:

𝜈
=
−
transverse strain
longitudinal strain
ν=−
longitudinal strain
transverse strain
​


Determines how much a material contracts sideways when stretched

3️⃣ Elastic Potential Energy Density

The energy stored per unit volume in an elastic material under stress is given by:

𝑢
=
1
2
𝜎
𝜖
u=
2
1
​

σϵ ⚡

Depends on Young’s modulus, stress, and strain

Helps quantify the work done in stretching or compressing a material

✅ Understanding these principles allows students to calculate energy stored in elastic materials and relate it to stress, strain, and material properties without memorizing isolated formulas.

🎯 Relevant For:

JEE Main Physics (January & April Attempts)

NEET Physics

Class 12 Physics (Elasticity and Mechanical Properties of Solids)

🔔 Watch the video to learn how stress, strain, and Poisson’s ratio influence elastic potential energy density in real materials ⚙️🧲

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