Скачать или смотреть LeetCode-345: Reverse Vowels of a String | Cracking coding interviews

Learn how to reverse the vowels in a string using the two-pointer technique in JavaScript! 🧠 This is a popular coding interview question that tests your understanding of pointers and string manipulation.

Problem link:- https://leetcode.com/problems/reverse...

1:58 - Solution explanation

In this video, we solve LeetCode-345: Reverse Vowels of a String — a popular problem often asked in coding interviews. Learn how to reverse only the vowels in a given string efficiently using the Two-Pointer Approach in JavaScript.

This tutorial is perfect for coding for beginners and anyone preparing for technical interviews, as it covers step-by-step logic, in-place string manipulation, and O(n) time complexity with minimal extra space.

With ElevateDev, you’ll understand how to approach string problems systematically, strengthen your problem-solving skills, and master techniques frequently asked in interviews. This is a must-watch for learners who want to learn coding and improve their DSA skills effectively.

Algorithm:-
Two-pointer technique:-
left = 0, right = s.length - 1
While left is less than right:
If s[left] is not a vowel → left++
Else if s[right] is not a vowel → right--
Else → swap s[left] and s[right], then left++, right--
This works because we're only interested in vowel characters,
and the goal is to reverse their positions.
So we scan from both ends and swap vowels in place.

Time Complexity: O(n)
Space Complexity: O(n) → due to split() and join() (can be O(1) with character array in languages like C++)

👉 Time Complexity: O(n)
👉 Space Complexity: O(n) (can be O(1) in C++ with character array)

This solution works efficiently by scanning the string from both ends and only swapping vowel characters.

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