Скачать или смотреть In contrast to the situation of Exercise 40 , experiments show that the reaction H_2+…

In contrast to the situation of Exercise 40 , experiments show that the reaction H_2+Br_2 →2 HBr satisfies the rate law d[HBr]/d t=k[H_2][Br_2]^1 / 2 and so for this reaction the differential equation becomes d x/d t=k(a-x)(b-x)^1 / 2 where x=[HBr] and a and b are the initial concentrations of hydrogen and bromine.
[ (a) Find x as a function of t in the case where a=b . Use the; fact that x(0)=0 .; (b) If a gt;b, find t as a function of x .[Hint : In performing the; integration, make the substitution u=√(b-x) . ] ]


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