Riemann surface of f(z)=sqrt(z)

Описание к видео Riemann surface of f(z)=sqrt(z)

The function f(z)=z^2 is not injective, e.g. 2^2 = (-2)^2 = 4. Thus sqrt(4) can be both 2 and -2.
This video explains the Riemann surface of sqrt(z), where sqrt(z^2) = z.
Domain Coloring has been used to visualize the complex-valued functions, see http://en.wikipedia.org/wiki/Domain_c....
4 maps are shown that cover the whole manifold.
In the end scene the zero-point is removed to illustrate how the surface can be addressed with cylinder coordinates.

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