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Скачать или смотреть How to Efficiently Collect Data from a Stream into Different Lists Based on Conditions in Java 8

  • vlogize
  • 2025-04-08
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How to Efficiently Collect Data from a Stream into Different Lists Based on Conditions in Java 8
How to collect data from a stream in different lists based on a condition?javajava 8
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Описание к видео How to Efficiently Collect Data from a Stream into Different Lists Based on Conditions in Java 8

Learn how to use Java 8 streams to collect data based on specific conditions, utilizing maps and sets for optimized performance and clarity.
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This video is based on the question https://stackoverflow.com/q/72948170/ asked by the user 'Pawan.Java' ( https://stackoverflow.com/u/14669745/ ) and on the answer https://stackoverflow.com/a/72948345/ provided by the user 'Thomas' ( https://stackoverflow.com/u/637853/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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Collecting Data from a Stream in Java 8

When working with streams in Java, you may find yourself needing to filter and group data based on certain conditions. For example, consider a scenario where you have a large dataset as a stream and need to categorize or collect data into separate lists based on a specific index. In this post, we will explore an efficient method of achieving this with Java 8 streams.

The Problem

Suppose you have a stream of data structured in a specific format, which is separated by delimiters. You wish to collect data based on index values—specifically, the third index that represents different entities like L100, L120, and so on. The stream of data is as follows:

[[See Video to Reveal this Text or Code Snippet]]

The goal is to filter this data based on values at index 2 and organize them into different lists corresponding to their entity names.

The Solution

To effectively collect the data from the stream, we recommend using a Map<String, List<String>>. This approach ensures that each entity name becomes a key in the map, with its corresponding values as a list. Here’s a step-by-step guide on how to implement this solution:

Step 1: Setup the Data and Constants

First, ensure that you have your data arranged in an array format. You will also set up a set of entity names you want to filter by:

[[See Video to Reveal this Text or Code Snippet]]

Step 2: Create the Stream

With your data ready, you can create a stream from the splittedLine array as follows:

[[See Video to Reveal this Text or Code Snippet]]

Advantages of This Approach

Performance: The algorithm operates efficiently with a complexity of O(n * log(m)), meaning it can handle larger datasets more swiftly than other methods that may run in O(n * m) time complexity.

Clarity: The solution is easier to follow due to its distinct steps. Here’s the breakdown:

Split and map the lines.

Filter out invalid lines early on.

Select only the entries that belong to your specified entities.

Group the valid lines by their respective entity names.

Conclusion

Using Java 8 streams to collect data into a map structure not only simplifies the process but also enhances performance and readability. By applying these techniques, you can manipulate and organize your data effectively, leading to clearer, more maintainable code.

For any Java developer, mastering streams is essential for handling data efficiently. Next time you’re faced with a similar scenario, remember this approach to help streamline your data handling tasks!

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