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Скачать или смотреть Binary Search Tree - 6 | 285. Inorder Successor in BST (Recursive)

  • CTO Bhaiya
  • 2025-06-07
  • 171
Binary Search Tree - 6 | 285. Inorder Successor in BST (Recursive)
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Описание к видео Binary Search Tree - 6 | 285. Inorder Successor in BST (Recursive)

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Inorder Successor in BST – Recursive Solution Explained (LeetCode 285)

📄 Description:
In this video, we delve into LeetCode Problem 285: Inorder Successor in BST, focusing on a recursive strategy to identify the inorder successor of a given node in a Binary Search Tree (BST).

🔍 What You'll Learn:
Understanding Inorder Successor: Grasp the concept of an inorder successor in the context of BSTs

Recursive Approach: Learn how to implement a recursive solution without relying on parent pointers

Step-by-Step Walkthrough: Follow a detailed explanation of the recursive algorithm, including base cases and recursive calls

Code Implementation: See the recursive solution coded in Python (or your language of choice), with clear annotations and explanations

Time and Space Complexity: Analyze the efficiency of the recursive approach in terms of time and space

CHAPTERS
0:00 Introduction
1:06 Intuition
5:30 What is smallest in a BST?
8:10 Pseudocode of the Recursive Approach
9:43 Inorder Successor using Inorder Traversal Simulation
15:00 Live Coding of Recursive Approach
21:45 Time & Space Complexity
23:30 One Simple Optimisation
24:12 Edge Case after Optimisation
26:55 Conclusion

📘 Problem Overview:
Given the root of a BST and a node p, the task is to find the node with the smallest key greater than p.val. This node is the inorder successor of p. If such a node doesn't exist, return None.

🧠 Recursive Strategy:
Base Case: If the current node is None, return None

Value Comparison:

If p.val less than node.val, the current node could be the successor → check the left subtree

Else, move to the right subtree

Return Successor: Whichever recursive call returns a valid successor is the answer

📈 Complexity Analysis:
Time Complexity: O(h), where h = height of the BST

Space Complexity: O(h) for the recursion stack

🔗 Additional Resources:
LeetCode 285: Inorder Successor in BST

Similar Problems: Validate BST, Lowest Common Ancestor

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#LeetCode #CodingInterview #DataStructures #BinarySearchTree #InorderSuccessor #RecursiveApproach #TechWithCTOBhaiya #LearnToCode #DSA #TechInterview #PythonCoding #JavaDeveloper #SoftwareEngineering #Algorithms



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