Скачать или смотреть Hackerrank c algorithms smart number solution debugging

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okay, let's dive deep into the "smart number" problem on hackerrank, focusing on debugging the c implementation. we'll break down the problem, explain the core logic, provide a working c code example, and then explore common debugging techniques to ensure your code runs correctly.

*problem statement*

the "smart number" problem (you can find it on hackerrank) is as follows:

a number is considered "smart" if it has an *odd number of positive divisors.*

you are given a list of numbers. for each number in the list, determine whether it is smart or not. output "true" if it's smart and "false" if it's not.

*example:*

*input:* `[1, 2, 3, 4, 5, 6, 7, 8, 9]`
*output:*


*explanation of the logic*

the key insight here is understanding the number of divisors a number possesses.

*pairs:* divisors usually come in pairs. for example, the divisors of 12 are (1, 12), (2, 6), and (3, 4).
*perfect squares:* the exception to the pairing rule is perfect squares. consider the number 9. its divisors are 1, 3, and 9. the divisor 3 is paired with itself (3 * 3 = 9). because one of the pairs is itself, the total number of divisors will be odd.
*conclusion:* a number has an odd number of divisors if and only if it is a perfect square.

therefore, to solve this problem, we just need to check if each input number is a perfect square.

*c code implementation*



*explanation of the c code:*

1. *includes:*
`stdio.h`: standard input/output library (for `scanf` and `printf`).
`stdbool.h`: introduces the `bool` data type and `true` and `false` keywords, making your code more readable.

2. *`is_smart_number(int num)` function:*
takes an integer `num` as input.
*handles edge cases:* checks if `num` is less than 1. if so, it's not a perfect square, so we return `false`. this is important to avoid potential errors with the square root calculation.
*square root approximation:* iterates through numbers from 1 up to the sq ...

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