Скачать или смотреть Day 9: LeetCode Daily Challenge – Maximize Happiness of Selected Children 🧠

Solving LeetCode 3075: Maximize Happiness of Selected Children.
This problem is all about making smart greedy choices, because every time you pick a child, the remaining kids lose 1 happiness 😬

The Logic (Greedy + Sorting):
1. Sort the happiness array in ascending order.
2. Always pick the child with the current maximum happiness.
3. After picking i children, the effective happiness becomes
max(0, originalHappiness − i).
4. Add this effective value to the total happiness.
5. Stop early if the effective happiness becomes 0.

This greedy strategy ensures we grab the happiest kids before jealousy ruins everything 😄

Complexity:
Time: O(N log N)
Space: O(1)

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