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Скачать или смотреть Extracting the N number of folders followed by filename from URLs using Regex in Python

  • vlogize
  • 2025-08-23
  • 1
Extracting the N number of folders followed by filename from URLs using Regex in Python
URL parsing: Get N number of folders followed by filename starting from a certain folderpythonregexurlparse
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Описание к видео Extracting the N number of folders followed by filename from URLs using Regex in Python

Discover how to effectively parse URLs and retrieve paths using Python and regex. Get the required folders and filename from complex URLs effortlessly!
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This video is based on the question https://stackoverflow.com/q/64160611/ asked by the user 'coredumped0x' ( https://stackoverflow.com/u/8108089/ ) and on the answer https://stackoverflow.com/a/64160687/ provided by the user 'Rakesh' ( https://stackoverflow.com/u/532312/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: URL parsing: Get N number of folders followed by filename starting from a certain folder

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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How to Extract the N Number of Folders Followed by a Filename from a URL in Python

In a world where web applications are becoming increasingly complex, the ability to manipulate and extract information from URLs is a crucial skill for developers. If you've found yourself needing to parse URLs to extract folders and filenames, you're in luck! Today, I’ll demonstrate how to effectively achieve this using Python and regular expressions.

The Problem

Imagine you have a URL that can vary in structure, but generally follows a pattern where it ends with a filename. Your task is to retrieve every element of the path after a specific part of the URL. For example, given the URL:

[[See Video to Reveal this Text or Code Snippet]]

You want to extract everything after the version number (/v87879798), resulting in:

[[See Video to Reveal this Text or Code Snippet]]

But what if the URL could change, leading to any number of folder layers like:

/v87879798/images/profile/oaz4wkjkjsbzxa3xlkmu.jpg

/v87879798/images/oaz4wkjkjsbzxa3xlkmu.jpg

/v87879798/oaz4wkjkjsbzxa3xlkmu.jpg

This can seem daunting, especially if you have limited knowledge of regular expressions and URL parsing. Let's break this down into simple steps.

The Solution

1. Use Regular Expressions

To tackle this problem, we can utilize Python's re module. Specifically, we need a regex pattern to match the version part of the URL and capture everything after it. The regex pattern we'll use is:

[[See Video to Reveal this Text or Code Snippet]]

Here’s what this pattern means:

v\d+ matches the letter v followed by one or more digits.

/ denotes the literal forward slash.

(.+ )$ captures everything after this slash until the end of the line, which corresponds to our desired path.

2. Implementing the Code

Let’s put this plan into action! Below is the complete code snippet that shows how to implement this extraction:

[[See Video to Reveal this Text or Code Snippet]]

3. Expected Output

After running the above code, the expected output will comprise:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

Using Python's regex capabilities makes URL parsing straightforward and efficient. By identifying a specific pattern in the URL, you can extract desired components with ease. This opens up various possibilities for developers dealing with dynamic web content where URL structures change frequently.

If you have any questions or need further assistance with regex or URL parsing in Python, feel free to reach out!

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