Скачать или смотреть 6 Palindrome Linked List Explained Step-by-Step | Slow & Fast Pointer Technique | DSA using Java

Confused about checking if a linked list is a palindrome?
In this video, I explain the exact interview-optimized approach using slow & fast pointers, list reversal, and a clear dry run — step by step.

In this video, you’ll learn how to check whether a singly linked list is a palindrome using the most efficient approach expected in coding interviews.

We cover this problem from first principles, not shortcuts.

✅ What you’ll learn:
What a palindrome linked list really means
Why naive approaches (array / stack) are not optimal
How the slow and fast pointer technique works
How to reverse the second half of a linked list safely
Step-by-step dry run with visuals
Full Java implementation
Edge cases interviewers love to test

📌 Problem Statement:
Given the head of a singly linked list, determine whether the list is a palindrome.

⏱️ Time & Space Complexity:
Time: O(n)
Space: O(1) (no extra data structures)

This explanation is perfect for:
DSA beginners
Java learners
Coding interview preparation

Anyone struggling with linked list pointers

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📌Chapters
00:00 - Problem Statement
00:25 - Algorithm
02:02 - Step 1: Finding the Middle Node
04:00 - Step 2: Reverse the Second Half
05:02 - Step 3: Compare Both Halves
07:01 - Full Code: Node Definition
07:10 - Finding Middle Node
08:44 - Reverse Second Half
09:33 - Compare both halves
10:52 - Restore the List
12:57 - Outro

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