Скачать или смотреть ✅Day 43 | LeetCode 169. Majority Element

🌟 Welcome to the Leetcode Daily Challenge Solution! 🚀



Prepare for an intriguing journey through the realm of algorithms and data manipulation as we tackle the majority element problem. Brace yourself for an exploration of algorithmic ingenuity and array traversal mastery.


🎯 Problem Overview:


Our mission is to find the majority element in a given array of integers, where the majority element appears more than ⌊n / 2⌋ times (where 'n' is the length of the array). We aim to devise an algorithm that efficiently identifies and returns the majority element.


🚀 Algorithm Breakdown:


Initialize variables 'count' and 'value' to keep track of the count of the current majority element and its value.
Iterate through the array 'nums' starting from the second element.
If the current element is the same as the majority element, increment 'count'; otherwise, decrement 'count'.
If 'count' becomes zero, update 'value' to the current index and reset 'count' to one, indicating a potential new majority element.
After iterating through the entire array, 'value' holds the index of the majority element.
Return the majority element.
📊 Complexity Analysis:


Time Complexity: O(n) - We traverse through the array once.
Space Complexity: O(1) - We use constant extra space for variables.


Delve into the intricacies of array traversal and majority element identification as we unravel the solution together! Feel empowered to explore, modify, and deepen your understanding of efficient strategies for finding the majority element in an array. 🔗✨


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