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Скачать или смотреть How to Access a Class from a Constant in Python: AUTH_USER_MODEL in Django

  • vlogize
  • 2025-07-25
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How to Access a Class from a Constant in Python: AUTH_USER_MODEL in Django
How to access constant with class pointer in python - AUTH_USER_MODEL = 'django_restframework_2fa.Uspythonpython 3.xdjangodjango rest framework
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Описание к видео How to Access a Class from a Constant in Python: AUTH_USER_MODEL in Django

Learn how to effectively access a Django user class using the `AUTH_USER_MODEL` constant in your Python application.
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This video is based on the question https://stackoverflow.com/q/67789328/ asked by the user 'Jeet Patel' ( https://stackoverflow.com/u/7790226/ ) and on the answer https://stackoverflow.com/a/67792089/ provided by the user 'Jeet Patel' ( https://stackoverflow.com/u/7790226/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to access constant with class pointer in python - AUTH_USER_MODEL = 'django_restframework_2fa.User'

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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How to Access a Class from a Constant in Python: AUTH_USER_MODEL in Django

In the world of Django development, you might come across situations where you need to access a class through a constant defined in your settings file. A common scenario is accessing the user class using the AUTH_USER_MODEL constant. This can seem a bit complex at first, but with clear steps, you can accomplish this without frustration. In this guide, we’ll break this down into understandable parts, providing you with an essential guide on how to do it.

The Problem

Suppose you're working on a Django application and have defined your custom user model like this in your settings.py:

[[See Video to Reveal this Text or Code Snippet]]

Here, django_restframework_2fa is the name of the package, and it contains a module named models where the User class is defined. Now, your intention is to create an instance of the User class using the AUTH_USER_MODEL constant.

You might think that calling it like this could work:

[[See Video to Reveal this Text or Code Snippet]]

However, this doesn’t yield the expected result. So, how can we go about solving this?

The Solution

To access the User class correctly using the AUTH_USER_MODEL constant, you need to use Python's import functionality more effectively. Here’s how you can do it step-by-step.

Step 1: Import the Required Functionality

You need to use the import_module() method from the importlib library. This allows you to dynamically import the module based on the string representation of the class you want to use.

Step 2: Define a Function to Retrieve the Class

Here’s a function that accomplishes the task of importing your class dynamically:

[[See Video to Reveal this Text or Code Snippet]]

Step 3: Using the Function

Now you can easily access the User class from your AUTH_USER_MODEL constant by calling the get_class() function like so:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

With this approach, you can efficiently access any class defined in your Django application using its constant string reference. Whether you’re working with user models or any other kind of class, using the above method will provide you with a reliable way to dynamically import and instantiate classes.

Feel free to adapt the get_class function as per your project structure, and remember that understanding how to retrieve classes dynamically can significantly enhance your efficiency as a developer.

By following these straightforward steps, you can overcome the initial hurdles of accessing classes through constants in Django and focus on building robust applications. Happy coding!

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