Скачать или смотреть Number of Boomerangs | LeetCode 447 | HashMap + Geometry Logic Explained | Python DSA

In this video, we’ll solve the Number of Boomerangs problem (LeetCode #447) using HashMap (dictionary) in Python 🐍.
You’ll learn how to count equal-distance pairs from a point and understand the geometry behind permutations (n × (n−1)) logic.

💡 Concept Covered:

How to calculate distance between 2D points efficiently

Using HashMap to group points by distance

How combinatorial logic (val * (val - 1)) counts ordered pairs

Step-by-step dry run with clear intuition

📦 Summary:
➡️ HashMap groups equal-distance points
➡️ Formula val * (val - 1) counts all valid boomerang permutations
➡️ Simple geometry + combinatorics = elegant O(N²) solution 💯

📌 GitHub Repository (Code + Notes):
👉 https://github.com/dearnidhi/Masterin...

📩 Contact:
✉️ Email: [email protected]

📸 Instagram: @codenidhi

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