Скачать или смотреть Swim in Rising Water | Leetcode 778 | Java | Hindi Explanation

Problem Link:
https://leetcode.com/problems/swim-in...
Solution Link:
https://github.com/kernelqueen/Leetco...
🌊 Approach – Dijkstra’s / Minimum Path with Priority Queue

We treat the grid as a graph where each cell has a height (time).

Use a min-heap (PriorityQueue) to always explore the lowest elevation cell first.

Keep track of the maximum height encountered so far — this represents the minimum time needed to reach that point.

The moment we reach the bottom-right cell, that max height is our answer.

⏱ Time Complexity: O(n² log n)
📦 Space Complexity: O(n²)

Key Concepts Used:

Dijkstra’s Algorithm (Modified BFS)

Priority Queue (Min-Heap)

Graph Traversal on Grid

Hashtags:
#LeetCode #Graph #DijkstrasAlgorithm #PriorityQueue #Java #CodingInterview #SwimInRisingWater #DSA


0:00 Problem Description
2:01 Problem Understanding
4:20 Approach for solving
6:00 Code
8:46 Time & Space Complexity