Скачать или смотреть CSIR NET June 2025 Part C | Question ID 562954176 | Conversion of IVP to Integral Equation

In this video, we solve CSIR NET June 2025 Mathematics Part C – Question ID 562954176.
The problem is based on the conversion of an Initial Value Problem (IVP) into a Volterra Integral Equation. We carefully explain how to transform the given differential equation:

y'' - 3y' + 2y = 4sin(x), y(0)=1, y'(0)=-2

into its equivalent integral form using the standard approach.

👉 This video will help you understand:

Step-by-step conversion of IVP to Integral Equation

Role of functions f(x) and Kernel K(x,t)

Application to CSIR NET Part C level problems

Key concepts useful for competitive exams like CSIR NET, GATE, IIT JAM, TIFR


If you are preparing for CSIR NET Mathematics 2025, this problem discussion will sharpen your problem-solving skills and strengthen your concepts of Differential Equations & Integral Equations.

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In this video we will solve a problem of CSIR NET June/July 2025 Mathematical Science paper. It is a question of part C based on the theory of Integral Equations. I hope strategy will help to solve similar type of problems asked in other equivalent exams like GATE , SET, IITJAM, ASSISTANT PROFESSOR EXAMS organized by various Public Service Commission, MSc Exam, TIFR etc.

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