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Скачать или смотреть How to Initialize List Short in One Line in Java?

  • vlogize
  • 2025-09-17
  • 0
How to Initialize List Short  in One Line in Java?
How to initialize List Short in one line?javalistinitializationshortlist initialization
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Описание к видео How to Initialize List Short in One Line in Java?

A guide on how to effectively initialize a `List Short ` in one line in Java using streams and collections.
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This video is based on the question https://stackoverflow.com/q/62966926/ asked by the user 'Методи Владимиров' ( https://stackoverflow.com/u/11576151/ ) and on the answer https://stackoverflow.com/a/62967227/ provided by the user 'Pandey Amit' ( https://stackoverflow.com/u/2599910/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to initialize List Short in one line?

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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How to Initialize List<Short> in One Line in Java?

In the world of Java programming, efficiently managing collections of data is essential. One common requirement is to initialize a List<Short> in a succinct manner. However, many developers encounter challenges in doing this, especially when trying to leverage more modern methods of collection initialization. In this post, we'll examine how to properly initialize a list of shorts in just one line, which can make your code cleaner and more efficient.

The Problem

You might be attempting to create a List<Short> in Java using the following syntax:

[[See Video to Reveal this Text or Code Snippet]]

However, this approach raises a compilation error, typically stating: "Cannot resolve constructor 'ArrayList(java.util.List<E>)'". This happens because you're trying to directly instantiate an ArrayList with a list of integers, which won't automatically convert them to shorts.

The Solution

To solve this problem, we can make use of Java Streams. This method allows for in-line conversions and is very effective for initializing lists with different data types. By using the Stream.of() method, we can convert integers to shorts and collect them into a list. Here is how you can do it:

Step-by-Step Guide

Import Required Packages:
Make sure to import the necessary classes at the top of your Java file:

[[See Video to Reveal this Text or Code Snippet]]

Use Stream for Conversion:
You can initiate a List<Short> in one line like this:

[[See Video to Reveal this Text or Code Snippet]]

Explanation

Stream.of(): This method creates a stream of the specified integers.

map() Method: The map() function applies a transformation to each element. Here, we're casting each integer to a short using value -> (short) value.intValue().

collect() Method: Finally, we use collect(Collectors.toList()) to gather the results into a List<Short>.

Complete Example

Here’s how your complete Java code may look:

[[See Video to Reveal this Text or Code Snippet]]

Output

When you run the above example, the output will be:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

Initializing a List<Short> in Java can be achieved efficiently using Java Streams. This approach not only resolves the issues of type conversion but also produces a clean and readable code structure. By embracing such techniques, you can enhance your coding practices and effortlessly manage collections in Java.

Implementing this one-liner can simplify your code and improve productivity as you no longer need to handle conversions in multiple steps.

Happy coding!

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