🎯 Welcome to Easy Maths with Faizan! 🎯
Hi Everyone!
I am Faizan, a professional instructor in Maths. I have a varied knowledge and experience in teaching maths at different levels.
Are you looking for clear, simple, and effective math lessons? You’re in the right place! Easy Maths with Faizan is dedicated to helping students understand complex mathematical concepts with ease.
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9th Class Maths | Exercise 7.2 Q 10, Q11,Q12,Q13 | Coordinate Geometry | Easy Maths with Faizan | New Syllabus 2025
Welcome to another detailed lecture on 9th Class Mathematics by Easy Maths with Faizan! In this video, we will solve Question 10, Question 11, Question 12, and Question 13 from Exercise 7.2 (Coordinate Geometry) of the New Syllabus 2025 for 9th Class. This lecture is specially designed for students who want step-by-step solutions with clear explanations in an easy and effective manner.
This video will be a complete guide for students to understand the slope of a line, slope intercept form, two intercept form, normal form, parallel lines, perpendicular lines, and conditions of parallelism and perpendicularity in coordinate geometry.
🔹 What You Will Learn in This Video:
Question 10 – Conversion of equations into
Slope intercept form
Two intercept form
Normal form
We will discuss in detail how to rearrange equations like 2x – 4y + 11 = 0, 4x + 7y – 2 = 0, and 15y – 8x + 3 = 0 into different forms using the slope formula and intercept method.
Question 11 – Checking the relation between two given lines:
Are they parallel?
Are they perpendicular?
Or are they neither parallel nor perpendicular?
With proper calculation of slopes, you will learn how to test conditions like m₁ = m₂ for parallel lines and m₁ × m₂ = –1 for perpendicular lines.
Question 12 – Equation of a line passing through (–4, 7) and parallel to 2x – 7y + 4 = 0. This question shows how to use the slope of a given line and apply it to find a new line equation when a point is given.
Question 13 – Equation of a line through (5, –8) and perpendicular to the line joining A(–15, –8) and B(10, 7). This question highlights how to find slope between two points, then use perpendicular slope condition to find the required equation.
🔹 Why This Lecture is Important:
Covers basic and advanced concepts of coordinate geometry in the 9th Class New Syllabus 2025.
Helps students understand slope method, equations of straight lines, and conditions for parallel and perpendicular lines.
Prepares you for board exams with clear step-by-step explanations.
Provides practical examples for slope, intercepts, and normal form which are commonly asked in exams.
🔹 About This Channel:
This channel, Easy Maths with Faizan, is dedicated to making mathematics simple, easy, and enjoyable for students of all levels, especially 9th Class students who are preparing with the New Syllabus 2025. Each lecture is carefully explained in a simple way so that even the most difficult questions become easy to understand.
If you are struggling with coordinate geometry, slopes, parallel lines, or perpendicular conditions, this video will clear all your doubts.
🔹 How This Video Helps You:
Builds strong concepts of straight line equations.
Shows different techniques to solve the same problem for better understanding.
Provides exam-oriented preparation with solved examples.
Boosts confidence in solving coordinate geometry questions in the board exams.
🔹 Watch This Video
✅ Complete solution of Exercise 7.2 Question 10, 11, 12, 13
✅ Easy step-by-step method of slope and intercepts
✅ Detailed explanation of parallel and perpendicular lines
✅ Full understanding of the New Syllabus 2025 topics
🏆 About Easy Maths with Faizan
Easy Maths with Faizan is a channel dedicated to making 9th Class Mathematics easier for every student. I cover all topics from the New Syllabus 2025, focusing on clear explanations and exam-focused solutions.
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