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LeetCode 1047 | Remove All Adjacent Duplicates in String | Using Stack & String | MAANG Preparation

In this video, we’ll solve LeetCode 1047 – Remove All Adjacent Duplicates in String, where we repeatedly remove pairs of adjacent duplicate characters until the string becomes stable.

This problem is a favorite in coding interviews at Amazon, Microsoft, Google, Meta, and Apple because it tests stack manipulation, string handling, and two-pointer techniques. It looks simple, but interviewers use it to check your edge case handling and optimization skills.

What you’ll learn in this video:

📖 Problem breakdown with dry run examples

🏗️ Stack-based solution (intuitive + easy to explain)

⚡ Optimized two-pointer solution (in-place, O(1) extra space)

🐞 Edge cases: empty string, no duplicates, all characters same

🏆 How to write clean, bug-free code interviewers love

🔑 Time & Space complexity explained with variations

Timestamps
00:00 Problem introduction with examples
02:30 Stack-based approach explained
07:00 Dry run walkthrough
10:00 Optimized Two-Pointer approach
14:00 Code walkthrough (stack & pointer solutions)
18:00 Edge cases & pitfalls
20:00 Time & Space complexity
22:00 Interview follow-up questions

📌 This video is part of our String + Stack Interview Series, following problems like LeetCode 844 (Backspace String Compare) and LeetCode 678 (Valid Parenthesis String).

🔥 If you’re preparing for MAANG/MANG roles, this problem is a must-master for string manipulation and stack fundamentals.

👉 Don’t forget to Like, Subscribe, and Share — let’s cross 1 Million views and help more candidates crack their interviews 🚀