Learn how to efficiently remove every `n-th` element from a Python list until only one element remains using a circular counting method.
---
This video is based on the question https://stackoverflow.com/q/65171399/ asked by the user 'K. Mary Hudson' ( https://stackoverflow.com/u/14719604/ ) and on the answer https://stackoverflow.com/a/65172278/ provided by the user 'Sachin Rajput' ( https://stackoverflow.com/u/12162608/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.
Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Every n-th element of a list
Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.
If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
How to Delete Every n-th Element of a Python List
If you're working with lists in Python, you might encounter a situation where you need to remove every n-th element until only one element remains. This can be an interesting problem, often posing some challenges in keeping track of the elements as they get removed in a circular fashion. In this guide, we’ll delve into a solution that efficiently handles this task.
The Problem Explained
Imagine you have a list of numbers, and you want to repeatedly delete every n-th element. Once you reach the end of the list, you reset your count to the beginning of the list, continuing this process until you're left with a single element.
Example:
For a list like [1, 2, 3, 4, 5, 6, 7, 8] with n=3, your deletion sequence would look like this:
Delete 3 (1, 2, 3, 4, 5, 6, 7, 8)
Delete 6 (4, 5, 6, 7, 8)
Continue counting and delete 1 (7, 8, 1...)
Eventually, you reach 7, which is the last remaining number.
This process can seem a bit complicated if done manually, but with code, it becomes manageable.
The Solution
Let’s break down the solution that correctly gets the job done. Here’s a step-by-step explanation of the solution:
Code Breakdown
We can employ a looping mechanism where we keep track of the index from which we need to delete the element:
[[See Video to Reveal this Text or Code Snippet]]
Explanation of the Code
Initialization:
We start with the list nums that contains our elements.
The variable pos is set to n-1 because list indices in Python start at zero (so, for n=3, we reference 2).
index keeps track of our current position in the list.
len_list holds the length of the list.
Removing Elements:
The while loop continues until only one element is left in the list (len_list > 1).
Inside the loop, we calculate the next index to remove using the formula:
[[See Video to Reveal this Text or Code Snippet]]
This formula ensures that we can wrap around to the beginning of the list when we reach the end.
Using pop:
We remove the element at the calculated index and print it. The pop method not only removes the item at the specified index but also returns it, which can be useful for logging or debugging.
Reducing the Length:
After each deletion, we decrease the len_list by one.
Finally, once the loop exits, we print the last remaining number in the list.
Output
If you helpfully run the provided code with the initial list and n=3, you will get the output:
[[See Video to Reveal this Text or Code Snippet]]
Conclusion
The method outlined here encapsulates the procedure to remove every n-th element from a list in a systematic and efficient manner using modular arithmetic. By leveraging Python’s built-in list methods, the solution becomes sleek and elegant.
Next time you’re faced with a similar problem, remember this strategy, and you'll find the solution to be a breeze!
Информация по комментариям в разработке