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CLASS 8|| NCERT|| CHAPTER -11 MENSURATION|| EXERCISE 11.1 QUESTION 1,2 ||NCERT MATHS WITH BARDEEP||

✅ In this video,
✔️ Class: 8
✔️ Subject: Maths
✔️ Chapter: Chapter 11 Mensuration
✔️ Topic Name: Exercise 11.1 Question 1,2

Question 1: A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?
Solution: (a) Square: Side of square s = 60 m
Perimeter = 4Xs = 4X60 = 240 m
(b) Rectangle: Length l = 80 m
Breadth b = ?
Perimeter = 2(l+b) = 2(80+b)
But perimeter is same
Therefore, 2(80+b) = 240
80+b = 240/2
80+b = 120
b = 120-80
b = 40
Breadth b = 40 m
Area of Square = sXs = 60X60 = 3600 Sq. m
Area of Rectangle = lXb = 80X 40 = 3200 Sq. m
Square has more area than Rectangle by 3600-3200 = 400 Sq. m

Question 2: Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs. 55 per Sq. m .
Solution : Let ABCD be the square plot
Side of ABCD s = 25 m
Area of ABCD = sXs = 25 X25 = 625 sq. m
Let EFGH be the house
Length of EFGH l = 20m
Breadth of EFGH b = 15 m
Area of EFGH = lXb = 20X15 = 300 Sq.m
Garden Area = Area of ABCD - Area of EFGH
= 625 - 300
= 325 Sq. m
Cost of developing Garden per sq. m = Rs 55
Total cost = 325X55
= Rs. 17875

Please click on the following links for any reference to the previous videos of this chapter:

Introduction    • CLASS 8|| NCERT|| CHAPTER-11 MENSURATION||...  

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