Скачать или смотреть 🔥 Tricky Series Problem | Find k Using Squares & Powers | JEE Maths Challenge | Maths With Vishal

In this video, we solve an interesting and tricky mathematics problem based on number series and summation formulas.
🔢 Given:
• α=12+42+82+132+192+262+…\alpha = 1^2 + 4^2 + 8^2 + 13^2 + 19^2 + 26^2 + \dotsα=12+42+82+132+192+262+… (up to 10 terms)
• β=∑n=110n4\beta = \sum_{n=1}^{10} n^4β=∑n=110n4
• 4α−β=55k+404\alpha - \beta = 55k + 404α−β=55k+40
🎯 Goal:
Find the value of k using smart observation and mathematical simplification.
✨ What you'll learn in this video:
• How to identify patterns in number series
• Quick techniques to handle square series
• Formula-based approach for ∑n4\sum n^4∑n4
• Useful tricks for JEE Main, JEE Advanced & Olympiad exams
📌 Perfect for students preparing for competitive exams or anyone who enjoys challenging math problems.
👉 Watch till the end for the complete solution and shortcut methods!
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